select count(*) from record where date > ′19991201′ and date < ′19991214′and amount > 2000 (25秒) select date,sum(amount) from record group by date (55秒) select count(*) from record where date > ′19990901′ and place in (′BJ′,′SH′) (27秒)
select count(*) from record where date > ′19991201′ and date < ′19991214′ and amount > 2000 (14秒) select date,sum(amount) from record group by date (28秒) select count(*) from record where date > ′19990901′ and place in (′BJ′,′SH′)(14秒)
select count(*) from record where date > ′19991201′ and date < ′19991214′ and amount > 2000 (26秒) select date,sum(amount) from record group by date (27秒) select count(*) from record where date > ′19990901′ and place in (′BJ, ′SH′)(< 1秒)
select count(*) from record where date > ′19991201′ and date < ′19991214′ and amount > 2000(< 1秒) select date,sum(amount) from record group by date (11秒) select count(*) from record where date > ′19990901′ and place in (′BJ′,′SH′)(< 1秒)
select * from record where substring(card_no,1,4)=′5378′(13秒) select * from record where amount/30< 1000(11秒) select * from record where convert(char(10),date,112)=′19991201′(10秒)
select * from record where card_no like ′5378%′(< 1秒) select * from record where amount < 1000*30(< 1秒) select * from record where date= ′1999/12/01′ (< 1秒)
你会发现SQL明显快起来!
2.例:表stuff有200000行,id_no上有非群集索引,请看下面这个SQL:
select count(*) from stuff where id_no in(′0′,′1′) (23秒)
分析:
where条件中的′in′在逻辑上相当于′or′,所以语法分析器会将in (′0′,′1′)转化为id_no =′0′ or id_no=′1′来执行。我们期望它会根据每个or子句分别查找,再将结果相加,这样可以利用id_no上的索引;但实际上(根据showplan),它却采用了"OR策略",即先取出满足每个or子句的行,存入临时数据库的工作表中,再建立唯一索引以去掉重复行,最后从这个临时表中计算结果。因此,实际过程没有利用id_no上索引,并且完成时间还要受tempdb数据库性能的影响。
create proc count_stuff as declare @a int declare @b int declare @c int declare @d char(10) begin select @a=count(*) from stuff where id_no=′0′ select @b=count(*) from stuff where id_no=′1′ end select @c=@a+@b select @d=convert(char(10),@c) print @d